Each of the following options consists of a high-tech field and a quantity. For each option, select Less than median if, based on the given information, the value of the quantity for that field is less than the median for that quantity over the 9 fields. Otherwise, select Greater than or equal to median._mofa留学圈mofaGRE在线题库系统_GRE在线搜题_GRE题库解析_GRE真题机经_GRE课程_GRE培训机构

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For 9 high-tech fields, the table provides data on all patent applications filed with the European Patent Office in 2012 for innovations in that field. For each field, the table lists three quantities: the number of applications filed, the number of applicants, and the average (arithmetic mean) number of applications per applicant (rounded to the nearest 0.01). Each application was assigned to exactly one field.

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Each of the following options consists of a high-tech field and a quantity. For each option, select Less than median if, based on the given information, the value of the quantity for that field is less than the median for that quantity over the 9 fields. Otherwise, select Greater than or equal to median.

Less than median Greater than or equal to median

Computer technology，number of applications

Digital communication，number of applicants

Organic chemistry and pharmaceuticals，average number of applications per applicant

正确答案： 2,1,1

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知识点概述
本题涉及数据整理与分析中的中位数计算和比较，以及平均数的概念。需要根据给定表格数据确定各字段相关数量的中位数，并与具体字段对应数量进行比较判断。解析
1. 对于“Number of applications”：将9个领域的申请数量从小到大排序，中间的数（第5个数）为中位数。排序后可知中位数为6633（Transport领域的申请数量）。Biotechnology领域申请数量5309小于中位数，选“Less than median”；Computer technology领域申请数量8288大于中位数，选“Greater than or equal to median” 等（其他领域类似比较）。 2. 对于“Number of applicants”：同理，将申请人数量从小到大排序找中位数。排序后确定中位数，再与各领域申请人数量比较判断。 3. 对于“Average number of applications per applicant”：把平均每个申请人的申请数量从小到大排序找中位数，然后对比各领域该数值进行判断。

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